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Trapezoid Rule

Suppose we take just two terms in the sum from Eq.(2) including just tex2html_wrap_inline139 with tex2html_wrap_inline141 and tex2html_wrap_inline143 . Then we have

equation15

What behavior of the function is consistent with taking just these two terms? We claim that if we include just the functions 1 and x and demand that keeping just two terms in the Taylor series, we can get tex2html_wrap_inline149 and tex2html_wrap_inline151 . Also, since we need just two weights for this lowest approximation, it makes sense that we would need behavior summarized in two pieces of information about the function's variation in the interval [a,b]. Another way of putting this is to say that taking the functions 1 and x amounts to a restriction to values of x which are close to zero, or thus necessarily values of a and b which are not too different.

So, let's demand that the integral of 1 and x over the interval tex2html_wrap_inline169 be exactly equal to the sum of two weights times two function values. That is we have

equation17

equation21

These represent two equations in two unknowns. When solved for tex2html_wrap_inline149 and tex2html_wrap_inline151 we find that

equation27

The resulting approximation to the integral is called the trapezoid rule. The formula is:

equation31

where tex2html_wrap_inline175 . Although we shall not show it here, it turns out to be the case that the error made when using the trapezoid rule is tex2html_wrap_inline177 , so that if h is small, then the error can become small. However, when h is not small, this approximation is just too crude to be of general utility. The rule is called the trapezoid rule because the formula amounts to approximating the integral assuming that the area under a trapezoid formed using the values of the function at the ends of the interval.



Comer Duncan
Tue Sep 23 17:09:49 EDT 1997